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20x^2-300x+700=0
a = 20; b = -300; c = +700;
Δ = b2-4ac
Δ = -3002-4·20·700
Δ = 34000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{34000}=\sqrt{400*85}=\sqrt{400}*\sqrt{85}=20\sqrt{85}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-20\sqrt{85}}{2*20}=\frac{300-20\sqrt{85}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+20\sqrt{85}}{2*20}=\frac{300+20\sqrt{85}}{40} $
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